Molar mass of silver bromide (AgBr)

The molar mass of silver bromide (AgBr) is 187.774 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Silver × 1 107.87 = 107.87
Bromine × 1 79.904 = 79.904
Total187.774 g/mol

Percent composition by element

  • Silver 57.45%
  • Bromine 42.55%

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H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

AgNO3 Silver nitrate AgCl Silver chloride Br2 Bromine HBr Hydrobromic acid KBr Potassium bromide NaBr Sodium bromide

FAQ

What is the molar mass of AgBr?

The molar mass of silver bromide (AgBr) is 187.774 g/mol.

How do you calculate the molar mass of AgBr?

Multiply the atomic mass of each element by the number of its atoms in AgBr, then add the results: 1 × 107.87 (Ag) + 1 × 79.904 (Br) = 187.774 g/mol.

What percentage of AgBr is Silver?

Silver makes up 57.45% of the mass of silver bromide (AgBr).