Molar mass of silver iodide (AgI)

The molar mass of silver iodide (AgI) is 234.77 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Silver × 1 107.87 = 107.87
Iodine × 1 126.9 = 126.9
Total234.77 g/mol

Percent composition by element

  • Silver 45.95%
  • Iodine 54.05%

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H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

AgNO3 Silver nitrate AgCl Silver chloride I2 Iodine KI Potassium iodide HI Hydroiodic acid NaI Sodium iodide

FAQ

What is the molar mass of AgI?

The molar mass of silver iodide (AgI) is 234.77 g/mol.

How do you calculate the molar mass of AgI?

Multiply the atomic mass of each element by the number of its atoms in AgI, then add the results: 1 × 107.87 (Ag) + 1 × 126.9 (I) = 234.77 g/mol.

What percentage of AgI is Iodine?

Iodine makes up 54.05% of the mass of silver iodide (AgI).