Molar mass of trinitrotoluene (C7H5N3O6)

The molar mass of trinitrotoluene (C7H5N3O6) is 227.132 g/mol.

TNT

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 7	12.011	= 84.077
Hydrogen	× 5	1.008	= 5.04
Nitrogen	× 3	14.007	= 42.021
Oxygen	× 6	15.999	= 95.994
Total			227.132 g/mol

Percent composition by element

Carbon 37.02%
Hydrogen 2.22%
Nitrogen 18.5%
Oxygen 42.26%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

C₈H₁₀N₄O₂ Caffeine CO(NH₂)₂ Urea C₈H₉NO₂ Acetaminophen C₃H₅N₃O₉ Nitroglycerin (NH₄)₂CO₃ Ammonium carbonate NH₄HCO₃ Ammonium bicarbonate

FAQ

What is the molar mass of C7H5N3O6?

The molar mass of trinitrotoluene (C7H5N3O6) is 227.132 g/mol.

How do you calculate the molar mass of C7H5N3O6?

Multiply the atomic mass of each element by the number of its atoms in C7H5N3O6, then add the results: 7 × 12.011 (C) + 5 × 1.008 (H) + 3 × 14.007 (N) + 6 × 15.999 (O) = 227.132 g/mol.

What percentage of C7H5N3O6 is Oxygen?

Oxygen makes up 42.26% of the mass of trinitrotoluene (C7H5N3O6).