Molar mass of iron disulfide (FeS2)

The molar mass of iron disulfide (FeS2) is 119.965 g/mol.

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Step-by-step calculation

ElementAtomsAtomic massSubtotal
Iron × 1 55.845 = 55.845
Sulfur × 2 32.06 = 64.12
Total119.965 g/mol

Percent composition by element

  • Iron 46.55%
  • Sulfur 53.45%

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H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

FeSO4 Iron(II) sulfate FeS Iron(II) sulfide Fe2(SO4)3 Iron(III) sulfate FeSO4·7H2O Iron(II) sulfate heptahydrate (NH4)2Fe(SO4)2·6H2O Ammonium iron(II) sulfate hexahydrate H2SO4 Sulfuric acid

FAQ

What is the molar mass of FeS2?

The molar mass of iron disulfide (FeS2) is 119.965 g/mol.

How do you calculate the molar mass of FeS2?

Multiply the atomic mass of each element by the number of its atoms in FeS2, then add the results: 1 × 55.845 (Fe) + 2 × 32.06 (S) = 119.965 g/mol.

What percentage of FeS2 is Sulfur?

Sulfur makes up 53.45% of the mass of iron disulfide (FeS2).