Molar mass of metformin (C4H11N5)

The molar mass of metformin (C4H11N5) is 129.167 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 4	12.011	= 48.044
Hydrogen	× 11	1.008	= 11.088
Nitrogen	× 5	14.007	= 70.035
Total			129.167 g/mol

Percent composition by element

Carbon 37.2%
Hydrogen 8.58%
Nitrogen 54.22%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

C₈H₁₀N₄O₂ Caffeine CO(NH₂)₂ Urea C₈H₉NO₂ Acetaminophen C₃H₅N₃O₉ Nitroglycerin C₇H₅N₃O₆ Trinitrotoluene HCN Hydrogen cyanide

FAQ

What is the molar mass of C4H11N5?

The molar mass of metformin (C4H11N5) is 129.167 g/mol.

How do you calculate the molar mass of C4H11N5?

Multiply the atomic mass of each element by the number of its atoms in C4H11N5, then add the results: 4 × 12.011 (C) + 11 × 1.008 (H) + 5 × 14.007 (N) = 129.167 g/mol.

What percentage of C4H11N5 is Nitrogen?

Nitrogen makes up 54.22% of the mass of metformin (C4H11N5).