Molar mass of lithium iron phosphate (LiFePO4)

The molar mass of lithium iron phosphate (LiFePO4) is 157.755 g/mol.

LFP

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Lithium	× 1	6.94	= 6.94
Iron	× 1	55.845	= 55.845
Phosphorus	× 1	30.974	= 30.974
Oxygen	× 4	15.999	= 63.996
Total			157.755 g/mol

Percent composition by element

Lithium 4.4%
Iron 35.4%
Phosphorus 19.63%
Oxygen 40.57%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

Fe₂O₃ Iron(III) oxide H₃PO₄ Phosphoric acid Ca₃(PO₄)₂ Calcium phosphate Na₃PO₄ Sodium phosphate K₃PO₄ Potassium phosphate LiOH Lithium hydroxide

FAQ

What is the molar mass of LiFePO4?

The molar mass of lithium iron phosphate (LiFePO4) is 157.755 g/mol.

How do you calculate the molar mass of LiFePO4?

Multiply the atomic mass of each element by the number of its atoms in LiFePO4, then add the results: 1 × 6.94 (Li) + 1 × 55.845 (Fe) + 1 × 30.974 (P) + 4 × 15.999 (O) = 157.755 g/mol.

What percentage of LiFePO4 is Oxygen?

Oxygen makes up 40.57% of the mass of lithium iron phosphate (LiFePO4).