Molar mass of lead(II) iodide (PbI2)

The molar mass of lead(II) iodide (PbI2) is 461 g/mol.

lead iodide

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Lead × 1 207.2 = 207.2
Iodine × 2 126.9 = 253.8
Total461 g/mol

Percent composition by element

  • Lead 44.95%
  • Iodine 55.05%

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H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

Pb(NO3)2 Lead(II) nitrate I2 Iodine KI Potassium iodide HI Hydroiodic acid NaI Sodium iodide PbO Lead(II) oxide

FAQ

What is the molar mass of PbI2?

The molar mass of lead(II) iodide (PbI2) is 461 g/mol.

How do you calculate the molar mass of PbI2?

Multiply the atomic mass of each element by the number of its atoms in PbI2, then add the results: 1 × 207.2 (Pb) + 2 × 126.9 (I) = 461 g/mol.

What percentage of PbI2 is Iodine?

Iodine makes up 55.05% of the mass of lead(II) iodide (PbI2).