Molar mass of lead(II) nitrate (Pb(NO3)2)

The molar mass of lead(II) nitrate (Pb(NO3)2) is 331.208 g/mol.

lead nitrate

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Lead	× 1	207.2	= 207.2
Nitrogen	× 2	14.007	= 28.014
Oxygen	× 6	15.999	= 95.994
Total			331.208 g/mol

Percent composition by element

Lead 62.56%
Nitrogen 8.46%
Oxygen 28.98%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

AgNO₃ Silver nitrate NaNO₃ Sodium nitrate NH₄NO₃ Ammonium nitrate C₈H₁₀N₄O₂ Caffeine HNO₃ Nitric acid NO Nitric oxide

FAQ

What is the molar mass of Pb(NO3)2?

The molar mass of lead(II) nitrate (Pb(NO3)2) is 331.208 g/mol.

How do you calculate the molar mass of Pb(NO3)2?

Multiply the atomic mass of each element by the number of its atoms in Pb(NO3)2, then add the results: 1 × 207.2 (Pb) + 2 × 14.007 (N) + 6 × 15.999 (O) = 331.208 g/mol.

What percentage of Pb(NO3)2 is Lead?

Lead makes up 62.56% of the mass of lead(II) nitrate (Pb(NO3)2).