Molar mass of barium sulfate (BaSO4)

The molar mass of barium sulfate (BaSO4) is 233.386 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Barium	× 1	137.33	= 137.33
Sulfur	× 1	32.06	= 32.06
Oxygen	× 4	15.999	= 63.996
Total			233.386 g/mol

Percent composition by element

Barium 58.84%
Sulfur 13.74%
Oxygen 27.42%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

H₂SO₄ Sulfuric acid CuSO₄ Copper(II) sulfate KAl(SO₄)₂·12H₂O Potassium alum MgSO₄ Magnesium sulfate SO₂ Sulfur dioxide CuSO₄·5H₂O Copper(II) sulfate pentahydrate

FAQ

What is the molar mass of BaSO4?

The molar mass of barium sulfate (BaSO4) is 233.386 g/mol.

How do you calculate the molar mass of BaSO4?

Multiply the atomic mass of each element by the number of its atoms in BaSO4, then add the results: 1 × 137.33 (Ba) + 1 × 32.06 (S) + 4 × 15.999 (O) = 233.386 g/mol.

What percentage of BaSO4 is Barium?

Barium makes up 58.84% of the mass of barium sulfate (BaSO4).