Molar mass of copper(II) sulfate pentahydrate (CuSO4·5H2O)

The molar mass of copper(II) sulfate pentahydrate (CuSO4·5H2O) is 249.677 g/mol.

blue vitriol

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Copper × 1 63.546 = 63.546
Sulfur × 1 32.06 = 32.06
Oxygen × 9 15.999 = 143.991
Hydrogen × 10 1.008 = 10.08
Total249.677 g/mol

Percent composition by element

  • Copper 25.45%
  • Sulfur 12.84%
  • Oxygen 57.67%
  • Hydrogen 4.04%

Copper(II) sulfate pentahydrate facts

  • Copper(II) sulfate pentahydrate forms bright blue crystals and is the most common form of copper sulfate.
  • It is used to make Bordeaux mixture, a traditional fungicide for grapevines, and in classrooms to grow large blue crystals.
  • When heated, it loses its water of crystallization and turns into white anhydrous copper(II) sulfate.

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

[Cu(NH3)4]SO4·H2O Tetraamminecopper(II) sulfate monohydrate H2SO4 Sulfuric acid CuSO4 Copper(II) sulfate KAl(SO4)2·12H2O Potassium alum H2SO3 Sulfurous acid Cu(OH)2 Copper(II) hydroxide

FAQ

What is the molar mass of CuSO4·5H2O?

The molar mass of copper(II) sulfate pentahydrate (CuSO4·5H2O) is 249.677 g/mol.

How do you calculate the molar mass of CuSO4·5H2O?

Multiply the atomic mass of each element by the number of its atoms in CuSO4·5H2O, then add the results: 1 × 63.546 (Cu) + 1 × 32.06 (S) + 9 × 15.999 (O) + 10 × 1.008 (H) = 249.677 g/mol.

What percentage of CuSO4·5H2O is Oxygen?

Oxygen makes up 57.67% of the mass of copper(II) sulfate pentahydrate (CuSO4·5H2O).