Molar mass of calcium nitrate tetrahydrate (Ca(NO3)2·4H2O)

The molar mass of calcium nitrate tetrahydrate (Ca(NO3)2·4H2O) is 236.146 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Calcium	× 1	40.078	= 40.078
Nitrogen	× 2	14.007	= 28.014
Oxygen	× 10	15.999	= 159.99
Hydrogen	× 8	1.008	= 8.064
Total			236.146 g/mol

Percent composition by element

Calcium 16.97%
Nitrogen 11.86%
Oxygen 67.75%
Hydrogen 3.41%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NH₄NO₃ Ammonium nitrate C₈H₁₀N₄O₂ Caffeine Ca(OH)₂ Calcium hydroxide HNO₃ Nitric acid NH₄OH Ammonium hydroxide HNO₂ Nitrous acid

FAQ

What is the molar mass of Ca(NO3)2·4H2O?

The molar mass of calcium nitrate tetrahydrate (Ca(NO3)2·4H2O) is 236.146 g/mol.

How do you calculate the molar mass of Ca(NO3)2·4H2O?

Multiply the atomic mass of each element by the number of its atoms in Ca(NO3)2·4H2O, then add the results: 1 × 40.078 (Ca) + 2 × 14.007 (N) + 10 × 15.999 (O) + 8 × 1.008 (H) = 236.146 g/mol.

What percentage of Ca(NO3)2·4H2O is Oxygen?

Oxygen makes up 67.75% of the mass of calcium nitrate tetrahydrate (Ca(NO3)2·4H2O).