Molar mass of iron(III) chloride hexahydrate (FeCl3·6H2O)

The molar mass of iron(III) chloride hexahydrate (FeCl3·6H2O) is 270.285 g/mol.

ferric chloride hexahydrate

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Iron	× 1	55.845	= 55.845
Chlorine	× 3	35.45	= 106.35
Hydrogen	× 12	1.008	= 12.096
Oxygen	× 6	15.999	= 95.994
Total			270.285 g/mol

Percent composition by element

Iron 20.66%
Chlorine 39.35%
Hydrogen 4.48%
Oxygen 35.52%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

HClO₄ Perchloric acid HClO Hypochlorous acid HClO₃ Chloric acid Fe(OH)₃ Iron(III) hydroxide Fe(NO₃)₃·9H₂O Iron(III) nitrate nonahydrate FeSO₄·7H₂O Iron(II) sulfate heptahydrate

FAQ

What is the molar mass of FeCl3·6H2O?

The molar mass of iron(III) chloride hexahydrate (FeCl3·6H2O) is 270.285 g/mol.

How do you calculate the molar mass of FeCl3·6H2O?

Multiply the atomic mass of each element by the number of its atoms in FeCl3·6H2O, then add the results: 1 × 55.845 (Fe) + 3 × 35.45 (Cl) + 12 × 1.008 (H) + 6 × 15.999 (O) = 270.285 g/mol.

What percentage of FeCl3·6H2O is Chlorine?

Chlorine makes up 39.35% of the mass of iron(III) chloride hexahydrate (FeCl3·6H2O).