Molar mass of iron(III) hydroxide (Fe(OH)3)

The molar mass of iron(III) hydroxide (Fe(OH)3) is 106.866 g/mol.

ferric hydroxide

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Iron × 1 55.845 = 55.845
Oxygen × 3 15.999 = 47.997
Hydrogen × 3 1.008 = 3.024
Total106.866 g/mol

Percent composition by element

  • Iron 52.26%
  • Oxygen 44.91%
  • Hydrogen 2.83%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

Fe(NO3)3·9H2O Iron(III) nitrate nonahydrate FeSO4·7H2O Iron(II) sulfate heptahydrate (NH4)2Fe(SO4)2·6H2O Ammonium iron(II) sulfate hexahydrate FeCl3·6H2O Iron(III) chloride hexahydrate NaOH Sodium hydroxide H2O Water

FAQ

What is the molar mass of Fe(OH)3?

The molar mass of iron(III) hydroxide (Fe(OH)3) is 106.866 g/mol.

How do you calculate the molar mass of Fe(OH)3?

Multiply the atomic mass of each element by the number of its atoms in Fe(OH)3, then add the results: 1 × 55.845 (Fe) + 3 × 15.999 (O) + 3 × 1.008 (H) = 106.866 g/mol.

What percentage of Fe(OH)3 is Iron?

Iron makes up 52.26% of the mass of iron(III) hydroxide (Fe(OH)3).