Molar mass of ammonium dichromate ((NH4)2Cr2O7)

The molar mass of ammonium dichromate ((NH4)2Cr2O7) is 252.063 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Nitrogen	× 2	14.007	= 28.014
Hydrogen	× 8	1.008	= 8.064
Chromium	× 2	51.996	= 103.992
Oxygen	× 7	15.999	= 111.993
Total			252.063 g/mol

Percent composition by element

Nitrogen 11.11%
Hydrogen 3.2%
Chromium 41.26%
Oxygen 44.43%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

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Related compounds

NH₄NO₃ Ammonium nitrate C₈H₁₀N₄O₂ Caffeine HNO₃ Nitric acid NH₄OH Ammonium hydroxide HNO₂ Nitrous acid CO(NH₂)₂ Urea

FAQ

What is the molar mass of (NH4)2Cr2O7?

The molar mass of ammonium dichromate ((NH4)2Cr2O7) is 252.063 g/mol.

How do you calculate the molar mass of (NH4)2Cr2O7?

Multiply the atomic mass of each element by the number of its atoms in (NH4)2Cr2O7, then add the results: 2 × 14.007 (N) + 8 × 1.008 (H) + 2 × 51.996 (Cr) + 7 × 15.999 (O) = 252.063 g/mol.

What percentage of (NH4)2Cr2O7 is Oxygen?

Oxygen makes up 44.43% of the mass of ammonium dichromate ((NH4)2Cr2O7).