Molar mass of tin(IV) oxide (SnO2)

The molar mass of tin(IV) oxide (SnO2) is 150.708 g/mol.

stannic oxide · cassiterite

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Tin × 1 118.71 = 118.71
Oxygen × 2 15.999 = 31.998
Total150.708 g/mol

Percent composition by element

  • Tin 78.77%
  • Oxygen 21.23%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

NaOH Sodium hydroxide H2O Water O2 Oxygen gas CaCO3 Calcium carbonate H2SO4 Sulfuric acid Fe2O3 Iron(III) oxide

FAQ

What is the molar mass of SnO2?

The molar mass of tin(IV) oxide (SnO2) is 150.708 g/mol.

How do you calculate the molar mass of SnO2?

Multiply the atomic mass of each element by the number of its atoms in SnO2, then add the results: 1 × 118.71 (Sn) + 2 × 15.999 (O) = 150.708 g/mol.

What percentage of SnO2 is Tin?

Tin makes up 78.77% of the mass of tin(IV) oxide (SnO2).