Molar mass of aluminum nitrate (Al(NO3)3)

The molar mass of aluminum nitrate (Al(NO3)3) is 212.994 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Aluminum × 1 26.982 = 26.982
Nitrogen × 3 14.007 = 42.021
Oxygen × 9 15.999 = 143.991
Total212.994 g/mol

Percent composition by element

  • Aluminum 12.67%
  • Nitrogen 19.73%
  • Oxygen 67.6%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

AgNO3 Silver nitrate NaNO3 Sodium nitrate KAl(SO4)2·12H2O Potassium alum NH4NO3 Ammonium nitrate Pb(NO3)2 Lead(II) nitrate C8H10N4O2 Caffeine

FAQ

What is the molar mass of Al(NO3)3?

The molar mass of aluminum nitrate (Al(NO3)3) is 212.994 g/mol.

How do you calculate the molar mass of Al(NO3)3?

Multiply the atomic mass of each element by the number of its atoms in Al(NO3)3, then add the results: 1 × 26.982 (Al) + 3 × 14.007 (N) + 9 × 15.999 (O) = 212.994 g/mol.

What percentage of Al(NO3)3 is Oxygen?

Oxygen makes up 67.6% of the mass of aluminum nitrate (Al(NO3)3).