Molar mass of sodium nitrate (NaNO3)

The molar mass of sodium nitrate (NaNO3) is 84.994 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Sodium	× 1	22.99	= 22.99
Nitrogen	× 1	14.007	= 14.007
Oxygen	× 3	15.999	= 47.997
Total			84.994 g/mol

Percent composition by element

Sodium 27.05%
Nitrogen 16.48%
Oxygen 56.47%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaNO₂ Sodium nitrite C₁₀H₁₄N₂Na₂O₈·2H₂O Disodium EDTA dihydrate C₅H₈NNaO₄ Monosodium glutamate C₁₄H₁₄N₃NaO₃S Methyl orange NaOH Sodium hydroxide NaHCO₃ Sodium bicarbonate

FAQ

What is the molar mass of NaNO3?

The molar mass of sodium nitrate (NaNO3) is 84.994 g/mol.

How do you calculate the molar mass of NaNO3?

Multiply the atomic mass of each element by the number of its atoms in NaNO3, then add the results: 1 × 22.99 (Na) + 1 × 14.007 (N) + 3 × 15.999 (O) = 84.994 g/mol.

What percentage of NaNO3 is Oxygen?

Oxygen makes up 56.47% of the mass of sodium nitrate (NaNO3).