Molar mass of barium chloride dihydrate (BaCl2·2H2O)

The molar mass of barium chloride dihydrate (BaCl2·2H2O) is 244.26 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Barium	× 1	137.33	= 137.33
Chlorine	× 2	35.45	= 70.9
Hydrogen	× 4	1.008	= 4.032
Oxygen	× 2	15.999	= 31.998
Total			244.26 g/mol

Percent composition by element

Barium 56.22%
Chlorine 29.03%
Hydrogen 1.65%
Oxygen 13.1%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

HClO₄ Perchloric acid HClO Hypochlorous acid Ba(OH)₂ Barium hydroxide HClO₃ Chloric acid Ba(OH)₂·8H₂O Barium hydroxide octahydrate CoCl₂·6H₂O Cobalt(II) chloride hexahydrate

FAQ

What is the molar mass of BaCl2·2H2O?

The molar mass of barium chloride dihydrate (BaCl2·2H2O) is 244.26 g/mol.

How do you calculate the molar mass of BaCl2·2H2O?

Multiply the atomic mass of each element by the number of its atoms in BaCl2·2H2O, then add the results: 1 × 137.33 (Ba) + 2 × 35.45 (Cl) + 4 × 1.008 (H) + 2 × 15.999 (O) = 244.26 g/mol.

What percentage of BaCl2·2H2O is Barium?

Barium makes up 56.22% of the mass of barium chloride dihydrate (BaCl2·2H2O).