Molar mass of barium hydroxide octahydrate (Ba(OH)2·8H2O)

The molar mass of barium hydroxide octahydrate (Ba(OH)2·8H2O) is 315.464 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Barium	× 1	137.33	= 137.33
Oxygen	× 10	15.999	= 159.99
Hydrogen	× 18	1.008	= 18.144
Total			315.464 g/mol

Percent composition by element

Barium 43.53%
Oxygen 50.72%
Hydrogen 5.75%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

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Related compounds

Ba(OH)₂ Barium hydroxide BaCl₂·2H₂O Barium chloride dihydrate NaOH Sodium hydroxide H₂O Water H₂SO₄ Sulfuric acid NaHCO₃ Sodium bicarbonate

FAQ

What is the molar mass of Ba(OH)2·8H2O?

The molar mass of barium hydroxide octahydrate (Ba(OH)2·8H2O) is 315.464 g/mol.

How do you calculate the molar mass of Ba(OH)2·8H2O?

Multiply the atomic mass of each element by the number of its atoms in Ba(OH)2·8H2O, then add the results: 1 × 137.33 (Ba) + 10 × 15.999 (O) + 18 × 1.008 (H) = 315.464 g/mol.

What percentage of Ba(OH)2·8H2O is Oxygen?

Oxygen makes up 50.72% of the mass of barium hydroxide octahydrate (Ba(OH)2·8H2O).