Molar mass of starch (glucose unit) (C6H10O5)

The molar mass of starch (glucose unit) (C6H10O5) is 162.141 g/mol.

cellulose unit

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 6	12.011	= 72.066
Hydrogen	× 10	1.008	= 10.08
Oxygen	× 5	15.999	= 79.995
Total			162.141 g/mol

Percent composition by element

Carbon 44.45%
Hydrogen 6.22%
Oxygen 49.34%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaHCO₃ Sodium bicarbonate C₂H₅OH Ethanol CH₃COOH Acetic acid C₇H₆O₂ Benzoic acid C₉H₈O₄ Aspirin C₇H₆O₃ Salicylic acid

FAQ

What is the molar mass of C6H10O5?

The molar mass of starch (glucose unit) (C6H10O5) is 162.141 g/mol.

How do you calculate the molar mass of C6H10O5?

Multiply the atomic mass of each element by the number of its atoms in C6H10O5, then add the results: 6 × 12.011 (C) + 10 × 1.008 (H) + 5 × 15.999 (O) = 162.141 g/mol.

What percentage of C6H10O5 is Oxygen?

Oxygen makes up 49.34% of the mass of starch (glucose unit) (C6H10O5).