Molar mass of ammonium acetate (CH3COONH4)

The molar mass of ammonium acetate (CH3COONH4) is 77.083 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 2	12.011	= 24.022
Hydrogen	× 7	1.008	= 7.056
Oxygen	× 2	15.999	= 31.998
Nitrogen	× 1	14.007	= 14.007
Total			77.083 g/mol

Percent composition by element

Carbon 31.16%
Hydrogen 9.15%
Oxygen 41.51%
Nitrogen 18.17%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

C₈H₁₀N₄O₂ Caffeine CO(NH₂)₂ Urea C₈H₉NO₂ Acetaminophen C₃H₅N₃O₉ Nitroglycerin C₇H₅N₃O₆ Trinitrotoluene (NH₄)₂CO₃ Ammonium carbonate

FAQ

What is the molar mass of CH3COONH4?

The molar mass of ammonium acetate (CH3COONH4) is 77.083 g/mol.

How do you calculate the molar mass of CH3COONH4?

Multiply the atomic mass of each element by the number of its atoms in CH3COONH4, then add the results: 2 × 12.011 (C) + 7 × 1.008 (H) + 2 × 15.999 (O) + 1 × 14.007 (N) = 77.083 g/mol.

What percentage of CH3COONH4 is Oxygen?

Oxygen makes up 41.51% of the mass of ammonium acetate (CH3COONH4).