Molar mass of borax (Na2B4O7·10H2O)

The molar mass of borax (Na2B4O7·10H2O) is 381.363 g/mol.

sodium tetraborate decahydrate

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Sodium	× 2	22.99	= 45.98
Boron	× 4	10.81	= 43.24
Oxygen	× 17	15.999	= 271.983
Hydrogen	× 20	1.008	= 20.16
Total			381.363 g/mol

Percent composition by element

Sodium 12.06%
Boron 11.34%
Oxygen 71.32%
Hydrogen 5.29%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaOH Sodium hydroxide NaHCO₃ Sodium bicarbonate H₃BO₃ Boric acid CH₃COONa Sodium acetate NaBH₄ Sodium borohydride Na₂CO₃·10H₂O Sodium carbonate decahydrate

FAQ

What is the molar mass of Na2B4O7·10H2O?

The molar mass of borax (Na2B4O7·10H2O) is 381.363 g/mol.

How do you calculate the molar mass of Na2B4O7·10H2O?

Multiply the atomic mass of each element by the number of its atoms in Na2B4O7·10H2O, then add the results: 2 × 22.99 (Na) + 4 × 10.81 (B) + 17 × 15.999 (O) + 20 × 1.008 (H) = 381.363 g/mol.

What percentage of Na2B4O7·10H2O is Oxygen?

Oxygen makes up 71.32% of the mass of borax (Na2B4O7·10H2O).