Molar mass of silver chromate (Ag2CrO4)

The molar mass of silver chromate (Ag2CrO4) is 331.732 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Silver × 2 107.87 = 215.74
Chromium × 1 51.996 = 51.996
Oxygen × 4 15.999 = 63.996
Total331.732 g/mol

Percent composition by element

  • Silver 65.03%
  • Chromium 15.67%
  • Oxygen 19.29%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

AgNO3 Silver nitrate K2Cr2O7 Potassium dichromate Ag2O Silver oxide K2CrO4 Potassium chromate (NH4)2Cr2O7 Ammonium dichromate NaOH Sodium hydroxide

FAQ

What is the molar mass of Ag2CrO4?

The molar mass of silver chromate (Ag2CrO4) is 331.732 g/mol.

How do you calculate the molar mass of Ag2CrO4?

Multiply the atomic mass of each element by the number of its atoms in Ag2CrO4, then add the results: 2 × 107.87 (Ag) + 1 × 51.996 (Cr) + 4 × 15.999 (O) = 331.732 g/mol.

What percentage of Ag2CrO4 is Silver?

Silver makes up 65.03% of the mass of silver chromate (Ag2CrO4).