Molar mass of barium carbonate (BaCO3)

The molar mass of barium carbonate (BaCO3) is 197.338 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Barium	× 1	137.33	= 137.33
Carbon	× 1	12.011	= 12.011
Oxygen	× 3	15.999	= 47.997
Total			197.338 g/mol

Percent composition by element

Barium 69.59%
Carbon 6.09%
Oxygen 24.32%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

CaCO₃ Calcium carbonate NaHCO₃ Sodium bicarbonate C₂H₅OH Ethanol CH₃COOH Acetic acid Na₂CO₃ Sodium carbonate CO Carbon monoxide

FAQ

What is the molar mass of BaCO3?

The molar mass of barium carbonate (BaCO3) is 197.338 g/mol.

How do you calculate the molar mass of BaCO3?

Multiply the atomic mass of each element by the number of its atoms in BaCO3, then add the results: 1 × 137.33 (Ba) + 1 × 12.011 (C) + 3 × 15.999 (O) = 197.338 g/mol.

What percentage of BaCO3 is Barium?

Barium makes up 69.59% of the mass of barium carbonate (BaCO3).