Molar mass of citric acid monohydrate (C6H8O7·H2O)

The molar mass of citric acid monohydrate (C6H8O7·H2O) is 210.138 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Carbon × 6 12.011 = 72.066
Hydrogen × 10 1.008 = 10.08
Oxygen × 8 15.999 = 127.992
Total210.138 g/mol

Percent composition by element

  • Carbon 34.29%
  • Hydrogen 4.8%
  • Oxygen 60.91%

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FAQ

What is the molar mass of C6H8O7·H2O?

The molar mass of citric acid monohydrate (C6H8O7·H2O) is 210.138 g/mol.

How do you calculate the molar mass of C6H8O7·H2O?

Multiply the atomic mass of each element by the number of its atoms in C6H8O7·H2O, then add the results: 6 × 12.011 (C) + 10 × 1.008 (H) + 8 × 15.999 (O) = 210.138 g/mol.

What percentage of C6H8O7·H2O is Oxygen?

Oxygen makes up 60.91% of the mass of citric acid monohydrate (C6H8O7·H2O).