Molar mass of potassium permanganate (KMnO4)

The molar mass of potassium permanganate (KMnO4) is 158.032 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Potassium	× 1	39.098	= 39.098
Manganese	× 1	54.938	= 54.938
Oxygen	× 4	15.999	= 63.996
Total			158.032 g/mol

Percent composition by element

Potassium 24.74%
Manganese 34.76%
Oxygen 40.5%

Potassium permanganate facts

Potassium permanganate is a dark purple, almost black crystalline solid that dissolves in water to form an intensely purple solution.
It is used to treat drinking water, to disinfect, and as an oxidizing agent in redox titrations.
In acidic titrations the purple permanganate ion is reduced to nearly colorless manganese(II) ions, so it acts as its own indicator.

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

KOH Potassium hydroxide KClO₃ Potassium chlorate KAl(SO₄)₂·12H₂O Potassium alum K₂Cr₂O₇ Potassium dichromate KNO₃ Potassium nitrate K₂CO₃ Potassium carbonate

FAQ

What is the molar mass of KMnO4?

The molar mass of potassium permanganate (KMnO4) is 158.032 g/mol.

How do you calculate the molar mass of KMnO4?

Multiply the atomic mass of each element by the number of its atoms in KMnO4, then add the results: 1 × 39.098 (K) + 1 × 54.938 (Mn) + 4 × 15.999 (O) = 158.032 g/mol.

What percentage of KMnO4 is Oxygen?

Oxygen makes up 40.5% of the mass of potassium permanganate (KMnO4).