Molar mass of lithium aluminum hydride (LiAlH4)

The molar mass of lithium aluminum hydride (LiAlH4) is 37.954 g/mol.

LAH

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Lithium × 1 6.94 = 6.94
Aluminum × 1 26.982 = 26.982
Hydrogen × 4 1.008 = 4.032
Total37.954 g/mol

Percent composition by element

  • Lithium 18.29%
  • Aluminum 71.09%
  • Hydrogen 10.62%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

KAl(SO4)2·12H2O Potassium alum LiOH Lithium hydroxide Al(OH)3 Aluminum hydroxide Al2Si2O5(OH)4 Kaolinite NaOH Sodium hydroxide NH3 Ammonia

FAQ

What is the molar mass of LiAlH4?

The molar mass of lithium aluminum hydride (LiAlH4) is 37.954 g/mol.

How do you calculate the molar mass of LiAlH4?

Multiply the atomic mass of each element by the number of its atoms in LiAlH4, then add the results: 1 × 6.94 (Li) + 1 × 26.982 (Al) + 4 × 1.008 (H) = 37.954 g/mol.

What percentage of LiAlH4 is Aluminum?

Aluminum makes up 71.09% of the mass of lithium aluminum hydride (LiAlH4).