Molar mass of aluminum hydroxide (Al(OH)3)

The molar mass of aluminum hydroxide (Al(OH)3) is 78.003 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Aluminum × 1 26.982 = 26.982
Oxygen × 3 15.999 = 47.997
Hydrogen × 3 1.008 = 3.024
Total78.003 g/mol

Percent composition by element

  • Aluminum 34.59%
  • Oxygen 61.53%
  • Hydrogen 3.88%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

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Related compounds

KAl(SO4)2·12H2O Potassium alum Al2Si2O5(OH)4 Kaolinite NaOH Sodium hydroxide H2O Water H2SO4 Sulfuric acid NaHCO3 Sodium bicarbonate

FAQ

What is the molar mass of Al(OH)3?

The molar mass of aluminum hydroxide (Al(OH)3) is 78.003 g/mol.

How do you calculate the molar mass of Al(OH)3?

Multiply the atomic mass of each element by the number of its atoms in Al(OH)3, then add the results: 1 × 26.982 (Al) + 3 × 15.999 (O) + 3 × 1.008 (H) = 78.003 g/mol.

What percentage of Al(OH)3 is Oxygen?

Oxygen makes up 61.53% of the mass of aluminum hydroxide (Al(OH)3).