Molar mass of magnesium nitrate (Mg(NO3)2)

The molar mass of magnesium nitrate (Mg(NO3)2) is 148.313 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Magnesium	× 1	24.305	= 24.305
Nitrogen	× 2	14.007	= 28.014
Oxygen	× 6	15.999	= 95.994
Total			148.313 g/mol

Percent composition by element

Magnesium 16.39%
Nitrogen 18.89%
Oxygen 64.72%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

MgNH₄PO₄·6H₂O Struvite C₅₅H₇₂MgN₄O₅ Chlorophyll a AgNO₃ Silver nitrate MgO Magnesium oxide NaNO₃ Sodium nitrate MgSO₄ Magnesium sulfate

FAQ

What is the molar mass of Mg(NO3)2?

The molar mass of magnesium nitrate (Mg(NO3)2) is 148.313 g/mol.

How do you calculate the molar mass of Mg(NO3)2?

Multiply the atomic mass of each element by the number of its atoms in Mg(NO3)2, then add the results: 1 × 24.305 (Mg) + 2 × 14.007 (N) + 6 × 15.999 (O) = 148.313 g/mol.

What percentage of Mg(NO3)2 is Oxygen?

Oxygen makes up 64.72% of the mass of magnesium nitrate (Mg(NO3)2).