Molar mass of aluminum oxide (Al2O3)

The molar mass of aluminum oxide (Al2O3) is 101.961 g/mol.

alumina

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Aluminum × 2 26.982 = 53.964
Oxygen × 3 15.999 = 47.997
Total101.961 g/mol

Percent composition by element

  • Aluminum 52.93%
  • Oxygen 47.07%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

KAl(SO4)2·12H2O Potassium alum Al(OH)3 Aluminum hydroxide Al2(SO4)3 Aluminum sulfate Al(NO3)3 Aluminum nitrate Al2Si2O5(OH)4 Kaolinite NaOH Sodium hydroxide

FAQ

What is the molar mass of Al2O3?

The molar mass of aluminum oxide (Al2O3) is 101.961 g/mol.

How do you calculate the molar mass of Al2O3?

Multiply the atomic mass of each element by the number of its atoms in Al2O3, then add the results: 2 × 26.982 (Al) + 3 × 15.999 (O) = 101.961 g/mol.

What percentage of Al2O3 is Aluminum?

Aluminum makes up 52.93% of the mass of aluminum oxide (Al2O3).