Molar mass of butyric acid (C3H7COOH)

The molar mass of butyric acid (C3H7COOH) is 88.106 g/mol.

butanoic acid

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 4	12.011	= 48.044
Hydrogen	× 8	1.008	= 8.064
Oxygen	× 2	15.999	= 31.998
Total			88.106 g/mol

Percent composition by element

Carbon 54.53%
Hydrogen 9.15%
Oxygen 36.32%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaHCO₃ Sodium bicarbonate C₂H₅OH Ethanol CH₃COOH Acetic acid C₇H₆O₂ Benzoic acid C₉H₈O₄ Aspirin C₇H₆O₃ Salicylic acid

FAQ

What is the molar mass of C3H7COOH?

The molar mass of butyric acid (C3H7COOH) is 88.106 g/mol.

How do you calculate the molar mass of C3H7COOH?

Multiply the atomic mass of each element by the number of its atoms in C3H7COOH, then add the results: 4 × 12.011 (C) + 8 × 1.008 (H) + 2 × 15.999 (O) = 88.106 g/mol.

What percentage of C3H7COOH is Carbon?

Carbon makes up 54.53% of the mass of butyric acid (C3H7COOH).