Molar mass of tartaric acid (C4H6O6)

The molar mass of tartaric acid (C4H6O6) is 150.086 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 4	12.011	= 48.044
Hydrogen	× 6	1.008	= 6.048
Oxygen	× 6	15.999	= 95.994
Total			150.086 g/mol

Percent composition by element

Carbon 32.01%
Hydrogen 4.03%
Oxygen 63.96%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaHCO₃ Sodium bicarbonate C₂H₅OH Ethanol CH₃COOH Acetic acid C₇H₆O₂ Benzoic acid C₉H₈O₄ Aspirin C₇H₆O₃ Salicylic acid

FAQ

What is the molar mass of C4H6O6?

The molar mass of tartaric acid (C4H6O6) is 150.086 g/mol.

How do you calculate the molar mass of C4H6O6?

Multiply the atomic mass of each element by the number of its atoms in C4H6O6, then add the results: 4 × 12.011 (C) + 6 × 1.008 (H) + 6 × 15.999 (O) = 150.086 g/mol.

What percentage of C4H6O6 is Oxygen?

Oxygen makes up 63.96% of the mass of tartaric acid (C4H6O6).