Molar mass of isoamyl acetate (C7H14O2)

The molar mass of isoamyl acetate (C7H14O2) is 130.187 g/mol.

isopentyl acetate · banana oil

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Carbon	× 7	12.011	= 84.077
Hydrogen	× 14	1.008	= 14.112
Oxygen	× 2	15.999	= 31.998
Total			130.187 g/mol

Percent composition by element

Carbon 64.58%
Hydrogen 10.84%
Oxygen 24.58%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaHCO₃ Sodium bicarbonate C₂H₅OH Ethanol CH₃COOH Acetic acid C₇H₆O₂ Benzoic acid C₉H₈O₄ Aspirin C₇H₆O₃ Salicylic acid

FAQ

What is the molar mass of C7H14O2?

The molar mass of isoamyl acetate (C7H14O2) is 130.187 g/mol.

How do you calculate the molar mass of C7H14O2?

Multiply the atomic mass of each element by the number of its atoms in C7H14O2, then add the results: 7 × 12.011 (C) + 14 × 1.008 (H) + 2 × 15.999 (O) = 130.187 g/mol.

What percentage of C7H14O2 is Carbon?

Carbon makes up 64.58% of the mass of isoamyl acetate (C7H14O2).