Molar mass of manganese dioxide (MnO2)

The molar mass of manganese dioxide (MnO2) is 86.936 g/mol.

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Manganese × 1 54.938 = 54.938
Oxygen × 2 15.999 = 31.998
Total86.936 g/mol

Percent composition by element

  • Manganese 63.19%
  • Oxygen 36.81%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

KMnO4 Potassium permanganate MnSO4 Manganese(II) sulfate NaOH Sodium hydroxide H2O Water O2 Oxygen gas CaCO3 Calcium carbonate

FAQ

What is the molar mass of MnO2?

The molar mass of manganese dioxide (MnO2) is 86.936 g/mol.

How do you calculate the molar mass of MnO2?

Multiply the atomic mass of each element by the number of its atoms in MnO2, then add the results: 1 × 54.938 (Mn) + 2 × 15.999 (O) = 86.936 g/mol.

What percentage of MnO2 is Manganese?

Manganese makes up 63.19% of the mass of manganese dioxide (MnO2).