Molar mass of manganese(II) sulfate (MnSO4)

The molar mass of manganese(II) sulfate (MnSO4) is 150.994 g/mol.

manganese sulfate

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Manganese	× 1	54.938	= 54.938
Sulfur	× 1	32.06	= 32.06
Oxygen	× 4	15.999	= 63.996
Total			150.994 g/mol

Percent composition by element

Manganese 36.38%
Sulfur 21.23%
Oxygen 42.38%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

H₂SO₄ Sulfuric acid CuSO₄ Copper(II) sulfate KAl(SO₄)₂·12H₂O Potassium alum MgSO₄ Magnesium sulfate SO₂ Sulfur dioxide CuSO₄·5H₂O Copper(II) sulfate pentahydrate

FAQ

What is the molar mass of MnSO4?

The molar mass of manganese(II) sulfate (MnSO4) is 150.994 g/mol.

How do you calculate the molar mass of MnSO4?

Multiply the atomic mass of each element by the number of its atoms in MnSO4, then add the results: 1 × 54.938 (Mn) + 1 × 32.06 (S) + 4 × 15.999 (O) = 150.994 g/mol.

What percentage of MnSO4 is Oxygen?

Oxygen makes up 42.38% of the mass of manganese(II) sulfate (MnSO4).