Molar mass of sodium citrate (Na3C6H5O7)

The molar mass of sodium citrate (Na3C6H5O7) is 258.069 g/mol.

trisodium citrate

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Sodium	× 3	22.99	= 68.97
Carbon	× 6	12.011	= 72.066
Hydrogen	× 5	1.008	= 5.04
Oxygen	× 7	15.999	= 111.993
Total			258.069 g/mol

Percent composition by element

Sodium 26.73%
Carbon 27.93%
Hydrogen 1.95%
Oxygen 43.4%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

NaHCO₃ Sodium bicarbonate CH₃COONa Sodium acetate Na₂CO₃·10H₂O Sodium carbonate decahydrate CH₃COONa·3H₂O Sodium acetate trihydrate C₁₀H₁₄N₂Na₂O₈·2H₂O Disodium EDTA dihydrate C₅H₈NNaO₄ Monosodium glutamate

FAQ

What is the molar mass of Na3C6H5O7?

The molar mass of sodium citrate (Na3C6H5O7) is 258.069 g/mol.

How do you calculate the molar mass of Na3C6H5O7?

Multiply the atomic mass of each element by the number of its atoms in Na3C6H5O7, then add the results: 3 × 22.99 (Na) + 6 × 12.011 (C) + 5 × 1.008 (H) + 7 × 15.999 (O) = 258.069 g/mol.

What percentage of Na3C6H5O7 is Oxygen?

Oxygen makes up 43.4% of the mass of sodium citrate (Na3C6H5O7).