Molar mass of magnesium sulfate heptahydrate (MgSO4·7H2O)

The molar mass of magnesium sulfate heptahydrate (MgSO4·7H2O) is 246.466 g/mol.

Epsom salt

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Magnesium × 1 24.305 = 24.305
Sulfur × 1 32.06 = 32.06
Oxygen × 11 15.999 = 175.989
Hydrogen × 14 1.008 = 14.112
Total246.466 g/mol

Percent composition by element

  • Magnesium 9.86%
  • Sulfur 13.01%
  • Oxygen 71.4%
  • Hydrogen 5.73%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

H2SO4 Sulfuric acid KAl(SO4)2·12H2O Potassium alum MgSO4 Magnesium sulfate CuSO4·5H2O Copper(II) sulfate pentahydrate Mg(OH)2 Magnesium hydroxide H2SO3 Sulfurous acid

FAQ

What is the molar mass of MgSO4·7H2O?

The molar mass of magnesium sulfate heptahydrate (MgSO4·7H2O) is 246.466 g/mol.

How do you calculate the molar mass of MgSO4·7H2O?

Multiply the atomic mass of each element by the number of its atoms in MgSO4·7H2O, then add the results: 1 × 24.305 (Mg) + 1 × 32.06 (S) + 11 × 15.999 (O) + 14 × 1.008 (H) = 246.466 g/mol.

What percentage of MgSO4·7H2O is Oxygen?

Oxygen makes up 71.4% of the mass of magnesium sulfate heptahydrate (MgSO4·7H2O).