Molar mass of zinc nitrate (Zn(NO3)2)

The molar mass of zinc nitrate (Zn(NO3)2) is 189.388 g/mol.

Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Zinc	× 1	65.38	= 65.38
Nitrogen	× 2	14.007	= 28.014
Oxygen	× 6	15.999	= 95.994
Total			189.388 g/mol

Percent composition by element

Zinc 34.52%
Nitrogen 14.79%
Oxygen 50.69%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

Could not read that formula

Related compounds

AgNO₃ Silver nitrate NaNO₃ Sodium nitrate NH₄NO₃ Ammonium nitrate Pb(NO₃)₂ Lead(II) nitrate C₈H₁₀N₄O₂ Caffeine HNO₃ Nitric acid

FAQ

What is the molar mass of Zn(NO3)2?

The molar mass of zinc nitrate (Zn(NO3)2) is 189.388 g/mol.

How do you calculate the molar mass of Zn(NO3)2?

Multiply the atomic mass of each element by the number of its atoms in Zn(NO3)2, then add the results: 1 × 65.38 (Zn) + 2 × 14.007 (N) + 6 × 15.999 (O) = 189.388 g/mol.

What percentage of Zn(NO3)2 is Oxygen?

Oxygen makes up 50.69% of the mass of zinc nitrate (Zn(NO3)2).