Molar mass of zinc sulfate heptahydrate (ZnSO4·7H2O)

The molar mass of zinc sulfate heptahydrate (ZnSO4·7H2O) is 287.541 g/mol.

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Step-by-step calculation

Element	Atoms	Atomic mass	Subtotal
Zinc	× 1	65.38	= 65.38
Sulfur	× 1	32.06	= 32.06
Oxygen	× 11	15.999	= 175.989
Hydrogen	× 14	1.008	= 14.112
Total			287.541 g/mol

Percent composition by element

Zinc 22.74%
Sulfur 11.15%
Oxygen 61.2%
Hydrogen 4.91%

Try another formula

H₂O NaCl CO₂ C₆H₁₂O₆ H₂SO₄ Ca(OH)₂ CuSO₄·5H₂O C₈H₁₀N₄O₂

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Related compounds

H₂SO₄ Sulfuric acid KAl(SO₄)₂·12H₂O Potassium alum CuSO₄·5H₂O Copper(II) sulfate pentahydrate H₂SO₃ Sulfurous acid ZnSO₄ Zinc sulfate (NH₄)₂SO₄ Ammonium sulfate

FAQ

What is the molar mass of ZnSO4·7H2O?

The molar mass of zinc sulfate heptahydrate (ZnSO4·7H2O) is 287.541 g/mol.

How do you calculate the molar mass of ZnSO4·7H2O?

Multiply the atomic mass of each element by the number of its atoms in ZnSO4·7H2O, then add the results: 1 × 65.38 (Zn) + 1 × 32.06 (S) + 11 × 15.999 (O) + 14 × 1.008 (H) = 287.541 g/mol.

What percentage of ZnSO4·7H2O is Oxygen?

Oxygen makes up 61.2% of the mass of zinc sulfate heptahydrate (ZnSO4·7H2O).