Molar mass of iron(II) oxide (FeO)

The molar mass of iron(II) oxide (FeO) is 71.844 g/mol.

ferrous oxide

Step-by-step calculation

ElementAtomsAtomic massSubtotal
Iron × 1 55.845 = 55.845
Oxygen × 1 15.999 = 15.999
Total71.844 g/mol

Percent composition by element

  • Iron 77.73%
  • Oxygen 22.27%

Try another formula

H2O NaCl CO2 C6H12O6 H2SO4 Ca(OH)2 CuSO4·5H2O C8H10N4O2

Could not read that formula

Related compounds

Fe2O3 Iron(III) oxide FeSO4 Iron(II) sulfate Fe3O4 Iron(II,III) oxide Fe(OH)3 Iron(III) hydroxide LiFePO4 Lithium iron phosphate Fe(NO3)3 Iron(III) nitrate

FAQ

What is the molar mass of FeO?

The molar mass of iron(II) oxide (FeO) is 71.844 g/mol.

How do you calculate the molar mass of FeO?

Multiply the atomic mass of each element by the number of its atoms in FeO, then add the results: 1 × 55.845 (Fe) + 1 × 15.999 (O) = 71.844 g/mol.

What percentage of FeO is Iron?

Iron makes up 77.73% of the mass of iron(II) oxide (FeO).